Question

This has been bugging me, I am given the steps to the answer, yet when I try to redo it I cannot reach the same answer. It is probably some silly mistake that I don't seem to notice, can someone please point my error, Thank you!

Context : Physics
The coefficient of friction between the block of mass m1 = 3.00 kg
and the surface in the figure below is μk = 0.395. The system starts
from rest. What is the speed of the ball of mass m2 = 5.00 kg when
it has fallen a distance h = 1.70 m?

a=g(m2-μkm1)/(m1+m2)
a= [(9.8) (5.00kg) - 0.395(3.00kg)] / (5.00kg) + (3.00kg)
a= 4.68 m/s^2

Yet when I try to do it myself, it give me a whole different number

Answer 1

a = g ( m2 - μk m1 ) / ( m1 + m2 ) =

9.81 ∙ ( 5 - 0.395 ∙ 3 ) / ( 5 + 3 ) =

9.81 ∙ ( 5 - 1.185 ) / 8 =

9.81 ∙ 3.815 / 8 =

37.42515 / 8 =

4.67814375

a = 4.68 m / s²

rounded on two decimal pieces