Question

Please help me solve this problem.
A plane flying at 75 m/s, was diving at an angle of 40 degrees below the horizontal when one of it's wheels fall off. The wheel hits the ground 8.5 s after it fell off the plane. I know the x and y components of the wheel as 57.5 and 48.2 m/s, respectively. But I don't know how to solve the other problems:
1. At what height did the wheel fall off the plane?
2. What horizontal distance did the wheel travel?
3. What was the wheel's velocity when it hit the ground?
Please help.

Answer 1

the wheel had an initial vertical velocity, and was then accelerated by gravity for 8.5 s

final vel y = init vel y + (8.5 s * g)

ave vel y = (final y + init y) / 2

ave vel y * 8.5s = height


horiz dist = x vel * 8.5 s


init K.E. + (m g h) = fin K.E.

(init vel)^2 + (2 g h) = (fin vel)^2

Answer 2

1. h = Vo*t + 0.5g*t^2 = 48.2 + 4.9*8.5^2 =

2. Xo * t = 57.5 * 8.5 =

3. V = Vo + g*t = 48.2 + 9.8*8.5 =