Asked by Shine Bright Shine Far
Steven analyzed a compound and found it to be 52.7% Potassium and 47.3% Chlorine. He determined the empirical formula to be
Answers
Answered by
bobpursley
Assume 1000 grams.
Moles K: 527/39=13.5
Moles Cl: 147/35=13.5
divide by lowest number to get ratio:
Moles K: 1.0
Moles Cl: 1.0
empirical formula= KCl
Moles K: 527/39=13.5
Moles Cl: 147/35=13.5
divide by lowest number to get ratio:
Moles K: 1.0
Moles Cl: 1.0
empirical formula= KCl
Answered by
Damon
Px Cly
total mass of a mol = 31 x + 35.5 y
fraction that is P = 31 x /(31x + 35.5y) = .527
fraction that is Cl = 35.5 y /(31x + 35.5y) = .473
=========================================
31 x = 16.337 x + 18.709 y ----> 14.663 x =18.709 y
35.5 y = 14.663x + 16.792 y---->14.663 x = 18.709y check
so y = 1.275 x
1275/1000 = 255/200 = 51/40 well about 5/4 maybe
P4Cl5
total mass of a mol = 31 x + 35.5 y
fraction that is P = 31 x /(31x + 35.5y) = .527
fraction that is Cl = 35.5 y /(31x + 35.5y) = .473
=========================================
31 x = 16.337 x + 18.709 y ----> 14.663 x =18.709 y
35.5 y = 14.663x + 16.792 y---->14.663 x = 18.709y check
so y = 1.275 x
1275/1000 = 255/200 = 51/40 well about 5/4 maybe
P4Cl5
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