Question
For the function:
a) integrate by hand to find the area under the curve btwn the given x-values
b) verify your answer to part (a) by having your calc graph the function and find the area (using command like Fnlnt or Sf(x)dx
f(x) = 1/x^3 from x=1 to x=4
a) integrate by hand to find the area under the curve btwn the given x-values
b) verify your answer to part (a) by having your calc graph the function and find the area (using command like Fnlnt or Sf(x)dx
f(x) = 1/x^3 from x=1 to x=4
Answers
what's the trouble? It's just a straightforward integration.
1/x^3 = x^-3, so
∫[1,4] x^-3 dx = -1/2 x^-2 [1,4] = (-1/2 * 4^-2)-(-1/2 * 1^-2) = -1/32 + 1/2 = 15/32
1/x^3 = x^-3, so
∫[1,4] x^-3 dx = -1/2 x^-2 [1,4] = (-1/2 * 4^-2)-(-1/2 * 1^-2) = -1/32 + 1/2 = 15/32
Related Questions
3) Consider rectangles located as shown in the first quadrant and inscribed under a decreasing curve...
A standard problem in mathematics is to measure the area under a curve (or to integrate the function...
Please help me the way through this sum Integrate Cos squared(3x) btwn x=pie/2 andx=0
The table below gives data points for the continuous function y = f(x).
ibb.co/2W0nQpC (Image link)...