Asked by Chris

Consider three lightbulbs each of which has a lifetime that is an independent exponential random variable with parameter λ=1. The variance of the time until all three burn out is:

=

Recall that the variance of an exponential with parameter λ is 1/λ2.

6 years ago

Answered by Anonymous

1/3 ?

5 years ago

Answered by drain

11/6 why it is wrong? could anyone explain this?

5 years ago

Answered by Anonymous

1/9 +1/4 + 1 = 1.361111

5 years ago

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Asked by Chris

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