Asked by Claire
What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 44 rpm (revolutions per minute) if the wheel's diameter is 31 cm?
Answers
Answered by
Damon
Radius = R = 0.31/2 meter
omega = angular velocity = 44 revs/min * 1 min/60 s * 2 pi rad/rev
= 4.61 rad/sec
so
Ac = omega^2 R = (4.61)^2 ^ 0.155
omega = angular velocity = 44 revs/min * 1 min/60 s * 2 pi rad/rev
= 4.61 rad/sec
so
Ac = omega^2 R = (4.61)^2 ^ 0.155
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