Asked by David

The total volume of the Rogers Center is 1.6 x 10^6 m cubed. If the volume of 100 peas is about 55 cm cubed, how many Rogers Centers would 6.02 x 10^23 peas fill?
Answered by Steve
100 peas/55cm^3 * (100cm/1m)^3 = 10^8/55 peas/m^3

6.02*10^23 peas / (10^8/55 peas/m^3) * 1RC/1.6*10^6m^3
= 6.02*10^23 * 55/10^8 / 1.6*10^6 = 206,937,500,000 RC
Answered by scott
be aware of significant figures
Answered by scott
(5.5E-7 m^3 / pea) * 6.02E23 peas / 1.6E6 m^3
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