Asked by Sandy
Mr. Rogers wants to fence in a rectangular garden next to a straight section of the Scioto
River. He has 330 feet of fencing to do the entire job. He doesn’t need fencing along the
river, and there is a 4.5 foot wide clearance for a gate at one end.
What are the dimensions of the garden (x and y) with the largest area.
Thanks!
River. He has 330 feet of fencing to do the entire job. He doesn’t need fencing along the
river, and there is a 4.5 foot wide clearance for a gate at one end.
What are the dimensions of the garden (x and y) with the largest area.
Thanks!
Answers
Answered by
Reiny
let the width be x
and the length be y
so we are given ....
2x - 4.5 + y = 330
y = 334.5 - 2x
area = xy
= x(334.5-2x)
= 334.5x - 2x^2
d(area)/dx = 334.5 - 4x = 0 for a max area
4x = 334.5
<b> x = 334.5/4 = 83.625
y = 334.5 - 2(83.625) = 167.25</b>
check:
167.25+83.625+83.625-4.5 = 330
area = xy = 13986.28125
let x = 83 , then y = 168.5
area = 13985.5 , a bit smaller
let x = 84 , then y = 166.5
area = xy = 13986 , also a bit smaller than the above
answer looks good.
and the length be y
so we are given ....
2x - 4.5 + y = 330
y = 334.5 - 2x
area = xy
= x(334.5-2x)
= 334.5x - 2x^2
d(area)/dx = 334.5 - 4x = 0 for a max area
4x = 334.5
<b> x = 334.5/4 = 83.625
y = 334.5 - 2(83.625) = 167.25</b>
check:
167.25+83.625+83.625-4.5 = 330
area = xy = 13986.28125
let x = 83 , then y = 168.5
area = 13985.5 , a bit smaller
let x = 84 , then y = 166.5
area = xy = 13986 , also a bit smaller than the above
answer looks good.