Asked by physics help
A piece of metal with an irregular shape has a mass of 4.281kg. When weighed while submerged in water, the piece of metal has an apparent mass of 4.000kg. What is the density of the metal? (Ans: 1.52x10⁴ kg/m³)
Answers
Answered by
R_scott
so it displaces .281 kg of water ... 281 cm^3
density = mass / volume = 4281 g / 281 cm^3
density = mass / volume = 4281 g / 281 cm^3
Answered by
Henry2
4.281 - 4.000 = 0.281 kg of water displaced.
0.281kg * 1m^3/1000kg = 2.81*10^-4 m^3 = Vol. of water displaced = Vol. of metal submerged.
Density = 4.281kg/2.81*10^-4m^3 = 1.52 *10^4 kg/m^3.
0.281kg * 1m^3/1000kg = 2.81*10^-4 m^3 = Vol. of water displaced = Vol. of metal submerged.
Density = 4.281kg/2.81*10^-4m^3 = 1.52 *10^4 kg/m^3.
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