Asked by Anonymous
A cable is used to lift a 310. kg crate upward, resulting in 7.82×103 N of tension in the rope. Using work and energy, solve for the speed of the crate after being lifted from rest to a height of 1.40 m above the floor.
Answers
Answered by
bobpursley
workdone=gaininPE + gaininKE
workdone=netforceup*distance=(7.82e3-mg)*1.40
gaininPE=mg*1.4
gaininKE=1/2 m v^2
solve for velocity v
workdone=netforceup*distance=(7.82e3-mg)*1.40
gaininPE=mg*1.4
gaininKE=1/2 m v^2
solve for velocity v