Asked by Tom

if an elevator starts from rest and rises with an acceleration of +0.29m/s^2. If each floor is 3m high,

a) how long does it take to pass the 12th floor?

b) how fast is the elevator going when it passes the 5th floor?

Answers

Answered by bobpursley
distance=1/2 a t^2
time=sqrt(2*3*12/.29)

vf=at=.29*time where time is sqrt(2*3*5 /.29)
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