Asked by charlie

Abel ,Belle and Cindy have $408 altogether. Belle has $7 more than Cindy And $5 more than Abel. how much does Abel have?
Answered by R_scott
A + B + C = 408

B = C + 7 = A + 5 ... A = B - 5 ... C = B - 7

solve by substitution
Answered by Henry2
Cindy has $X.
Belle has $(X+7).
Abel has $(X+7)-5.

x + (x+7) + (x+7)-5 = 408.
3x = 399,
X = 133.
Abel amt. = (x+7)-5 = (133 + 7)- 5 = $135.
Answered by charlie
Thank you for your quick response. It is very clear.
Charlie

Answered by Henry2
Glad I could help.
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