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Solve the logarithmic equation. Round to the nearest ten-thousandth if necessary. log 8x^3=4 Can someone walk me through this?Asked by helana
Solve the logarithmic equation. Round to the nearest ten-thousandth if necessary.
log 8x^3=4
can someone walk me through this step by step?
log 8x^3=4
can someone walk me through this step by step?
Answers
Answered by
Steve
log 8x^3=4
assuming base 10, that means
8x^3 = 10^4 = 10000
x^3 = 10000/8 = 10 * (10/2)^3
x = 5∛10 ≈ 10.77217
assuming base 10, that means
8x^3 = 10^4 = 10000
x^3 = 10000/8 = 10 * (10/2)^3
x = 5∛10 ≈ 10.77217
Answered by
helana
thank you so much!
Answered by
helana
could u explain to me how u got the last part though?i don't think i am putting it in my calc right because every time i do it ends up being 395.284707521047
Answered by
Bosnian
If your question mean:
log₈( x³ ) = 4
then:
3 ∙ log₈ ( x ) = 4
log₈ ( x ) = 4 / 3
x = 8 ^ ( 4 / 3 )
x = ∛ 8⁴
x = ∛ 4096
x = 16
log₈( x³ ) = 4
then:
3 ∙ log₈ ( x ) = 4
log₈ ( x ) = 4 / 3
x = 8 ^ ( 4 / 3 )
x = ∛ 8⁴
x = ∛ 4096
x = 16
Answered by
helana
that's not what it means,but thanks for helping!
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