initial KE + forcedownhill*distance=friction*distance
1/2 m v^2 + mg*sin30*d=mg*mu*d
dg( *sin30-mu)=-1/2 v^2
solve for distance d.
An Olympic skier moving at 20.0 m/s down a 30.0 degrees slope encounters a region of wet snow, of coefficient of friction uk = 0.740. How far down the slope does she go before stopping?
1 answer