Asked by Yahya Shekha

A load of 500N is raised through 5m by a machine when it's effort E moves simultaneously through a distance of 25m along it's direction. If the machine has efficiency of 80% , calculate
a) Total work done by machine.
b) Value of E
Answered by Yahya Shekha
Total work done by the machine is 5,625J.
Value of E is 125N.
Answered by Damon
output work = 500 * 5 = 2500 Joules
work in = work out/.8 = 2500/.8 = 3125 Joules

E * 25 = 3125
E= 125 Newtons
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