Asked by Anonymous
A student solved the scalar equations for different planes as stated below. Explain why each equation is not the best representation for the equation for a plane. (4)
(a) 2x+4y−6z+24=0
(b) −2x+y−2z+5=0
for a is it because you can factor a 2 out of the equation?
and for b is it because of the negative infront of the equation? and can it be fixed by factoring a -1 out of the equation?
(a) 2x+4y−6z+24=0
(b) −2x+y−2z+5=0
for a is it because you can factor a 2 out of the equation?
and for b is it because of the negative infront of the equation? and can it be fixed by factoring a -1 out of the equation?
Answers
Answered by
Reiny
I agree, the first can be reduced to
x + 2y - 3z + 12 = 0
for the 2nd, it is normal practise to start the equation with a positive coefficient of x, so
2x - y + 2z - 5 = 0
x + 2y - 3z + 12 = 0
for the 2nd, it is normal practise to start the equation with a positive coefficient of x, so
2x - y + 2z - 5 = 0
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