Asked by april
On his way off to college, Russell drags his bag 15.0 m from the door of his house to the car at a constant speed with a horizontal force of 95.0 N. How much work does Russell do to overcome the force of friction?
Answers
Answered by
bobpursley
work=force*distance.
The work he did is the same as work done on friction.
The work he did is the same as work done on friction.
Answered by
april
but the answer in my book is 1430, and i got 1425
Answered by
Noether
That's probably because of significant figures. 15.0 m and 95.0 N both have three significant figures. Therefore, the answer should also have three significant figures. 1425 rounded to three sigfigs is 1430.
Answered by
april
thanks
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