Asked by Kim

Determine the number and type of solutions for the quadratic equation:

4X^2 + 3X= -8

Answers

Answered by scott
4 x^2 + 3 x + 8 = 0

the nature of the discriminant determines the type of solutions

b^2 - 4 a c = 9 - 32 = -23 ... negative and not a perfect square
... the solutions are imaginary , two complex conjugates
Answered by Damon
4 x^2 + 3x +8 = 0
b^2-4ac = 9 - 128
Negative so solutions are complex
Answered by scott
Damon got the right value for the discriminant

final result doesn't change
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