Asked by Kim
Determine the number and type of solutions for the quadratic equation:
4X^2 + 3X= -8
4X^2 + 3X= -8
Answers
Answered by
scott
4 x^2 + 3 x + 8 = 0
the nature of the discriminant determines the type of solutions
b^2 - 4 a c = 9 - 32 = -23 ... negative and not a perfect square
... the solutions are imaginary , two complex conjugates
the nature of the discriminant determines the type of solutions
b^2 - 4 a c = 9 - 32 = -23 ... negative and not a perfect square
... the solutions are imaginary , two complex conjugates
Answered by
Damon
4 x^2 + 3x +8 = 0
b^2-4ac = 9 - 128
Negative so solutions are complex
b^2-4ac = 9 - 128
Negative so solutions are complex
Answered by
scott
Damon got the right value for the discriminant
final result doesn't change
final result doesn't change
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