Asked by Ande2
Find the zeros of the polynomial f(x)=2x3-7x2-3x+18
Answers
Answered by
scott
(2 * 27) - (7 * 9) - (3 * 3) + 18 = 0
(2x3-7x2-3x+18) / (x - 3) = 2 x^2 - x - 6
(2x3-7x2-3x+18) / (x - 3) = 2 x^2 - x - 6
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