Asked by Anonymous
Find all zeros of the polynomial. (Enter your answers as a comma-separated list.)
P(x) = x3 − 11x2 + 33x − 35
P(x) = x3 − 11x2 + 33x − 35
Answers
Answered by
Reiny
type exponents this way:
P(x) = x^3 - 11x^2 + 33x - 35
try values of x = ±1, ±5, ±7
arggh, the last one P(7) worked
P(7) = 343 - 11(49) + 33(7) - 35 = 0
so x-7 is a factor
after sysnthetic division:
P(x) = (x-7)(x^2 - 4x + 5) = 0
x = 7 or by formula, x = (4 ± √-4)/2
= 2 ± 2i
x = 7, 2 ± 2i
don't know if you want only real roots
P(x) = x^3 - 11x^2 + 33x - 35
try values of x = ±1, ±5, ±7
arggh, the last one P(7) worked
P(7) = 343 - 11(49) + 33(7) - 35 = 0
so x-7 is a factor
after sysnthetic division:
P(x) = (x-7)(x^2 - 4x + 5) = 0
x = 7 or by formula, x = (4 ± √-4)/2
= 2 ± 2i
x = 7, 2 ± 2i
don't know if you want only real roots
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