Asked by Anonymous
The metal ion M2+ in ammonia, NH3 forms the complex ion M(NH3)62+ (Kf = 5.1x108). Calculate the M2+ concentration when the equilibrium concentrations of NH3 and M(NH3)62+ are 0.074 and 0.22 M respectively
Answers
Answered by
DrBob222
M^2+ + 6NH3 ==> [M(NH3)6]^2+
Write the Kf expression for the above reaction, plug in the equilibrium concentrations of NH3 and the complex and solve for (M^2+). This is a simple one to do.
Write the Kf expression for the above reaction, plug in the equilibrium concentrations of NH3 and the complex and solve for (M^2+). This is a simple one to do.
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