Asked by Anonymous
The joint PMF,
p
X
,
Y
(
x
,
y
)
, of the random variables
X
and
Y
is given by the following table:
y
=
1
4
c
0
2
c
8
c
y
=
0
3
c
2
c
0
2
c
y
=
β
1
2
c
0
c
4
c
x
=
β
2
x
=
β
1
x
=
0
x
=
1
p
X
,
Y
(
x
,
y
)
, of the random variables
X
and
Y
is given by the following table:
y
=
1
4
c
0
2
c
8
c
y
=
0
3
c
2
c
0
2
c
y
=
β
1
2
c
0
c
4
c
x
=
β
2
x
=
β
1
x
=
0
x
=
1
Answers
Answered by
Steve - eh?
how about reformatting your text so it makes some sense?
Answered by
john doe
The joint PMF, ππ,π(π₯,π¦), of the random variables π and π is given by the following table:
π¦=1 4π 0 2π 8π
π¦=0 3π 2π 0 2π
π¦=β1 2π 0 π 4π
π₯=β2 π₯=β1π₯=0 π₯=1
c=?
pX(1)=?
if π=π2π3 then π[πβ£π=β1] = ?
Conditioned on the event that πβ 0 , are π and π independent?
π΅πΊπ(πβ£π=0)= ? if X=0
π¦=1 4π 0 2π 8π
π¦=0 3π 2π 0 2π
π¦=β1 2π 0 π 4π
π₯=β2 π₯=β1π₯=0 π₯=1
c=?
pX(1)=?
if π=π2π3 then π[πβ£π=β1] = ?
Conditioned on the event that πβ 0 , are π and π independent?
π΅πΊπ(πβ£π=0)= ? if X=0
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