Asked by qwerty
Consider the following joint PMF of the random variables X and Y:
pX,Y(x,y)={1/72⋅(x2+y2),if x∈{1,2,4} and y∈{1,3}, 0, otherwise}.
1. P(Y<X)=
2. P(Y=X)=
3. Find the marginal PMF pX(x).
pX(1)=
pX(2)=
pX(3)=
pX(4)=
4. Find E[X] and E[XY].
E[X]=
E[XY]=
5. var(X)=
6. Let A denote the event X≥Y. Find E[X∣A].
E[X∣A]=
pX,Y(x,y)={1/72⋅(x2+y2),if x∈{1,2,4} and y∈{1,3}, 0, otherwise}.
1. P(Y<X)=
2. P(Y=X)=
3. Find the marginal PMF pX(x).
pX(1)=
pX(2)=
pX(3)=
pX(4)=
4. Find E[X] and E[XY].
E[X]=
E[XY]=
5. var(X)=
6. Let A denote the event X≥Y. Find E[X∣A].
E[X∣A]=
Answers
Answered by
malier
1.47/22
2.1/36
3a.12/72
3b.1/4
3c.0
3d.42/72
4.3
5.???
6.1.5
7.??
2.1/36
3a.12/72
3b.1/4
3c.0
3d.42/72
4.3
5.???
6.1.5
7.??
Answered by
Jhon
1???
2 2/72
3a 12/72
3b 1/4
3c 0
3d 42/72
4a 3
4b 61/9
5 3/2
6 173/47
2 2/72
3a 12/72
3b 1/4
3c 0
3d 42/72
4a 3
4b 61/9
5 3/2
6 173/47
Answered by
sist pist
1. 47/72
Answered by
RVE
c= 5/64
P(Y<X)= 83/128
P(Y=X)= 1/32
P(X=1)= 10/64
P(X=2)= 17/64
P(X=3)= 0
P(X=4)= 37/64
E[X]= 3
E[XY]= 227/32
var(X)= 3/2
P(Y<X)= 83/128
P(Y=X)= 1/32
P(X=1)= 10/64
P(X=2)= 17/64
P(X=3)= 0
P(X=4)= 37/64
E[X]= 3
E[XY]= 227/32
var(X)= 3/2
Answered by
Pedro
c= 1/128
P(Y<X)= 83/128
P(Y=X)= 1/32
P(X=1)= 10/64
P(X=2)= 17/64
P(X=3)= 0
P(X=4)= 37/64
E[X]= 3
E[XY]= 227/32
VAR(X)= 3/2
P(Y<X)= 83/128
P(Y=X)= 1/32
P(X=1)= 10/64
P(X=2)= 17/64
P(X=3)= 0
P(X=4)= 37/64
E[X]= 3
E[XY]= 227/32
VAR(X)= 3/2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.