Asked by Barber Dabor
A motor car accelerate for 10sec to attain a velocity of 20m/s. If continues and then decelerate so that is stop in 20sec. calculate (1) Acceleration (2) Deceleration (3) The Distance
Answers
Answered by
bobpursley
what does "If continues' MEAN?
Answered by
Henry
1. a*t = 20 m/s. a*10 = 20, a = 2m/s^2.
2. V = Vo + a*t = 0. 20 + a*20 = 0, a = -1.0 m/s^2.
3. d1 = 0.5a*t^2 = 0.5*2*10^2 = 100 m.
V^2 = Vo^2 + 2a*d2 = 0.
20^2 + (-2)*d2 = 0, d2 = ?.
d = d1 + d2.
2. V = Vo + a*t = 0. 20 + a*20 = 0, a = -1.0 m/s^2.
3. d1 = 0.5a*t^2 = 0.5*2*10^2 = 100 m.
V^2 = Vo^2 + 2a*d2 = 0.
20^2 + (-2)*d2 = 0, d2 = ?.
d = d1 + d2.
Answered by
Barber Dabor
I need the solution for the distance
Answered by
Henry
Please add d1 and d2 to get the distance.
Can YOU solve the simple Eq.. to get d2 ??.
Can YOU solve the simple Eq.. to get d2 ??.
Answered by
Jibrin usman guni
D1 D2
Answered by
Viki
please I need the calculation
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