A 1.92 × 103 kg car accelerates uniformly from rest to 12.4 m/s in 3.77 s.

Question

What is the work done on the car in this time interval?

Answer 1

a=(V-Vo)/t = (12.4-0)/3.77 = 3.29 m/s^2

d = 0.5*3.29*3.77^2 = 23.37 m.

Work = F*d = (m*g) * d=(1920*9.8)23.37 =
439,805 Joules.