Asked by Raven
Differentiate.
y = (4x)/9 − cot(x)
y = (4x)/9 − cot(x)
Answers
Answered by
Damon
dy/dx = (4/9) + csc^2 x
note
d/dx (cos x/sin x )= [-sin^2 x - cos^2 x] /sin^2 x = -1/sin^2 x = -csc^2 x
note
d/dx (cos x/sin x )= [-sin^2 x - cos^2 x] /sin^2 x = -1/sin^2 x = -csc^2 x
Answered by
Raven
Thank you for your help, but the website is telling me that answer is wrong.
Answered by
Steve
Maybe you wrote it wrong. If you meant
y = (4x)/(9 − cot(x))
then
y' = [(4)(9-cotx)-(4x)(csc^2x)]/(9-cotx)^2
maybe rearranged a bit.
y = (4x)/(9 − cot(x))
then
y' = [(4)(9-cotx)-(4x)(csc^2x)]/(9-cotx)^2
maybe rearranged a bit.