The rule coming into play here is:
(a^x)(b^x) = (ab)^x
apply it, and let me know what you get
Multiply: (4xy^2)^1/5 and (8x^2y)^1/5
2 answers
(4xy^2)^1/5 * (8x^2y)^1/5 = (4xy^2 * 8x^2y)^1/5 = (32x^3y^3)^1/5 =
(2^5x^3y^3)^1/5 = 2(x^3*y^3)^1/5 = 2(x^3/5y^3/5).
(2^5x^3y^3)^1/5 = 2(x^3*y^3)^1/5 = 2(x^3/5y^3/5).