Asked by Amit
Integrate by the function 2cosx/3sin²x
Answers
Answered by
Reiny
∫ 2cosx/3sin²x dx
= ∫ (2/3) cosx (sinx)^-2 dx
= (-2/3) (sinx)^-1 + c
or -2/(3sinx) + c
or (-2/3)csc x + c
I did it by inspection, noting the the derivative of the power sin^2 x showed up as the correct cosx in the product
= ∫ (2/3) cosx (sinx)^-2 dx
= (-2/3) (sinx)^-1 + c
or -2/(3sinx) + c
or (-2/3)csc x + c
I did it by inspection, noting the the derivative of the power sin^2 x showed up as the correct cosx in the product
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