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solve: 2cosx-1=0
1 answer
cosx = 1/2 , the cosine is positive in I and IV
x = 60° or 300°
or x = π/3 or x = 5π/3
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For the following equation, why cannot I not solve it? I keep getting an error.
-- 2cosx - 3 = 0 -- I first isolated for "x"
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tanx+secx=2cosx
(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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Find the limit of
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Find the volume of the solid obtained by rotating the region in the first quadrant enclosed by the curves y= tanx and y=2cosx
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