Describe how you would prepare 0.5N sulphuric acid in 500mls specific gravity 1.84,percent purity 98

Answer 1

The wording is confusing. I'm assuming you want to prepare 500 ml of 0.5 N H2SO4 and you're starting with H2SO4 of specific gravity 1.84 g/mL and 98% purity.
What's the normality of the H2SO4, That's
1.84 g/mL x 1000 mL x 0.98 x (1/49) = ? N.= approx 36 N but you need to use a more accurate number.
Then mL1 x N1 = mL2 x N2 or
500mL x 0.5N = mL2 x 36N and solve for the mL2.
Then pipet mL2 from the pure 98% H2SO4 into a 500 mL flask THAT ALREADY CONTAINS SOME H2O (say 250 mL or so) and fill to the mark. Shake and stopper.