Asked by Jacob
You want to calculate the displacement of an object thrown over a bridge. Using -10 m/s2 for acceleration due to gravity, what would be the total displacement of the object if it took 8 seconds before hitting the water?
Answers
Answered by
Reiny
for your situation
distance = -5t^2 , if it was dropped. If it was thrown with some velocity up or down , we would have to know that
so distance = -5(8^2) = -320 m , negative because downwards
(tall bridge, considering that the tallest bridge in the US, The Royal Gorge bridge, is about 290 m)
distance = -5t^2 , if it was dropped. If it was thrown with some velocity up or down , we would have to know that
so distance = -5(8^2) = -320 m , negative because downwards
(tall bridge, considering that the tallest bridge in the US, The Royal Gorge bridge, is about 290 m)