Asked by Majiri
                Calculate the length of a displaced pendulum Bob which pass through its lowest point twice every second. Take g=10m/s²
            
            
        Answers
                    Answered by
            Scott
            
    it passes a point once every second
... so the period is 2 seconds
period = 2 π √(length / g)
2 = 2 π √(L / 10) ... L = 10 / π^2
    
... so the period is 2 seconds
period = 2 π √(length / g)
2 = 2 π √(L / 10) ... L = 10 / π^2
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.