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Asked by Majiri

Calculate the length of a displaced pendulum Bob which pass through its lowest point twice every second. Take g=10m/s²
8 years ago

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Answered by Scott
it passes a point once every second
... so the period is 2 seconds

period = 2 π √(length / g)

2 = 2 π √(L / 10) ... L = 10 / π^2
8 years ago

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