Use distributive property
(n-1)(n^2-3n+4)
= n (n^2-3n+4) - 1 (n^2-3n+4)
= n^3 -3 n^2 + 4 n -n^2 + 3 n - 4
collect like terms
= n^3 -4 n^2 + 7 n - 4
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n^2 (n^2+2) + 2 (n^2+2)
= n^4 + 2 n^2 + 2 n^2 + 4
= n^4 + 4 n^2 + 4
or simply FOIL (n^2+2)(n^2+2)
turn these factored equastions into expanded form:
(n-1)(n^2-3n+4)
(n^2+2)^2
3 answers
use distributive property to factor each expression:1. x^2+8x+16
2. d^2+8d+7 3. y^2+6y+8 4. b^2-2b-3 5. s^2-4s-5
2. d^2+8d+7 3. y^2+6y+8 4. b^2-2b-3 5. s^2-4s-5
Grace, you are jesting. We are not going to do that for you, it will not help you learn if we do the practice. We will be happy to critique your work.
2 answers