Asked by GRACE

turn these factored equastions into expanded form:
(n-1)(n^2-3n+4)

(n^2+2)^2
Answered by Damon
Use distributive property
(n-1)(n^2-3n+4)

= n (n^2-3n+4) - 1 (n^2-3n+4)

= n^3 -3 n^2 + 4 n -n^2 + 3 n - 4

collect like terms

= n^3 -4 n^2 + 7 n - 4

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n^2 (n^2+2) + 2 (n^2+2)

= n^4 + 2 n^2 + 2 n^2 + 4

= n^4 + 4 n^2 + 4

or simply FOIL (n^2+2)(n^2+2)
Answered by GRACE
use distributive property to factor each expression:1. x^2+8x+16
2. d^2+8d+7 3. y^2+6y+8 4. b^2-2b-3 5. s^2-4s-5
Answered by bobpursley
Grace, you are jesting. We are not going to do that for you, it will not help you learn if we do the practice. We will be happy to critique your work.
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