Asked by jen
What weight of Ca(OH)2 is necessary to prepare 3,500ml of 0.7M of Ca(OH)2 solution?
Answers
Answered by
bobpursley
you want to have 3.5*.7 moles Ca(OH)2
mass needed= .7(3.5)*formulamass Ca(OH2)
mass needed= .7(3.5)*formulamass Ca(OH2)
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