Asked by Britney
A rectangular piece of metal is 15in longer than it is wide. Squares with sides 3 in long are cut from four corners and the flaps are folded up to form an open box. If the volume is 1218in^3, what we’re the original deminsions of the piece of metal?
Answers
Answered by
Leo Galleguillos
Interesting. Are you able to visualize this? Any idea how to get started?
Answered by
Britney
X^2+3x-1272=0
Needs to be factored
Needs to be factored
Answered by
Reiny
original piece is x by x+15
base of box = x-6 by x+9
height of box = 3
volume = 3(x-6)(x+9) = 1218
x^2 + 3x - 54 = 406
x^2 + 3x - 460 = 0
(x - 20)(x + 23) = 0
x = 20 or a negative
the original piece was 20 by 35 inches
base of box = x-6 by x+9
height of box = 3
volume = 3(x-6)(x+9) = 1218
x^2 + 3x - 54 = 406
x^2 + 3x - 460 = 0
(x - 20)(x + 23) = 0
x = 20 or a negative
the original piece was 20 by 35 inches
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