Asked by Anonymous
                C (3,4) tangent to the line y=1/3x-1/3
            
            
        Answers
                    Answered by
            bobpursley
            
    I do not understand what you are asking. 
    
                    Answered by
            Anonymous
            
    I wanna know the radius of the circle
    
                    Answered by
            Steve
            
    The distance from a point (h,k) to the line Ax^2+Bx+C=0 is
|Ah+Bk+C|/√(A^2+B^2)
We can avoid messy fractions if we rewrite the line as
x-3y-1=0
So, that means the radius of your circle is
|1*3-3*4-1|/√(1^2+3^2) = 10/√10 = √10
Now you know the center and the radius, so just put into standard circle form.
    
|Ah+Bk+C|/√(A^2+B^2)
We can avoid messy fractions if we rewrite the line as
x-3y-1=0
So, that means the radius of your circle is
|1*3-3*4-1|/√(1^2+3^2) = 10/√10 = √10
Now you know the center and the radius, so just put into standard circle form.
                    Answered by
            Anonymous
            
    Thank you 
    
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