Rennata Gas is driving through town at 25.0 m/s and begins to accelerate at a constant rate of -1.0m/s^2. Eventually Rennata comes to a complete stop. Use kinematic equations to calculate the distance which Rennata travels while decelerating.

Answer 1

vf^2=vi^2+2ad
d=Vi^2/2a=25^2/(2)=625/2 m

Answer 2

The distance traveled can be found by calculating the area between the line on the graph and the axes.
distance = 0.5*bh
distace = 0.5*(25.0 s)*(25.0 m/s)
distance = 313 m