Question
Construct trapezium PQRS where PQ is parallel to SR, PQ=7cm,Q=60°, QR=5cm and RS=4cm.Calculate its area.
Answers
Steve
the altitude is QR sin 60° = 5 * √3/2
So, the area is
A = (B+b)/2 * h = (4+7)/2 * 5/2 √3 = 55√3/4
So, the area is
A = (B+b)/2 * h = (4+7)/2 * 5/2 √3 = 55√3/4