Question

A body is projected at an angle of 30 degree with the horizontal at initial speed of 200m/s. In how many seconds will it reach the ground? How far from the point of projection will it strike?

Answer 1

there is a "range equation"

wikipedia is a good source

Answer 2

You should have memorized two equations:
a. hf=hi+v*time+1/2 a t^2
where hf, hi are initiial velocities, v is the velocity in the direction of h, and a is the acceleration in the direction of height. In this case, it yields in upward motion..
hf=hi+muzzlevelocity*sinTheta*t-4.9t^2 and since hf, hi=0, you can find time of flight rather quickly.
b. distance equation: distance=velocity*time where velocity is in the direction of distance.
Here, range=v*cosTheta*time

And, if you look below, a number of the related equations are helpful.

Answer 3

a. Vo = 200m/s[30o].
Xo = 200*Cos30 = 173.2 m/s.
Yo = 200*sin30 = 100 m/s.

Y = Yo + g*Tr = 0,
100 + (-9.8)Tr = 0,
Tr = 10.2 s. = Rise time.

Tf = Tr = 10.2 s. = Fall time.
Tr+Tf = 10.2 + 10.2 = 20.4 s. = Time to reach Gnd.

Answer 4

b. d = Xo*(Tr + Tf) = 173.2 * 20.4

Answer 5

please help me solve this: A body is projected upward at an angle of 30° with the horizontal at an initial speed of 200m/s. In how many seconds will it reach the ground? How far from the point of projection will it strike?

Answer 6

Yeah