Asked by Chris
Earth is a spherical body, of radius 6,376 km, which completes a full rotation about its axis in 24.0 h. how long (in hours) should the day on Earth be so that a person at the equator is able to float freely above the ground?
Answers
Answered by
bobpursley
acceleration due to gravity=9.8m/s^2
centripetal acceleration=w^2 *r (r is given, w=2PI/(T*3600) rad/s
set them equal, solve for Period T.
9.8=4PI^2/(T^2*3600^2)
T=2PI/3600 sqrt(1/9.8) check my math, T is in hours.
centripetal acceleration=w^2 *r (r is given, w=2PI/(T*3600) rad/s
set them equal, solve for Period T.
9.8=4PI^2/(T^2*3600^2)
T=2PI/3600 sqrt(1/9.8) check my math, T is in hours.
Answered by
Douglas Allan
what is PI?
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