A force acts for 5 seconds on a body of mass 5.2 kg initially at rest. The force then ceases to act and the body moves with a speed of 3m/s find magnitude of force
4 answers
Not understood
final Ke = (1/2) m v^2 = (1/2)(5.2)(3)^2 = 23.4 Joules
work in = force * distance = F * d = 23.4
what is distance?
average speed = 3/2 = 1.5 m/s
d = 1.5 m/s * 5 s = 7.5 meters
so
F* 7.5 = 23.4
F = 23.4 / 7.5
work in = force * distance = F * d = 23.4
what is distance?
average speed = 3/2 = 1.5 m/s
d = 1.5 m/s * 5 s = 7.5 meters
so
F* 7.5 = 23.4
F = 23.4 / 7.5
Average speed is d/t not d*t
The answer is 78N
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