Asked by Hammad
A force of 5.0 N acts on a 15 kg body initially at rest. Compute the work done by the force in (a) the first,(b) the second, and (c) the third seconds and (d) the instantaneous power due to the force at the end of the third second.
Answers
Answered by
Chanz
I'm guessing we're ignoring friction.
a = F/m
v = at
and KE = Work = 1/2mv^2
for part d) P = W/t
a = F/m
v = at
and KE = Work = 1/2mv^2
for part d) P = W/t
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