Asked by Merin rose
What is the mass of glucose required to prepare 500ml of 1M solution
Answers
Answered by
Damon
0.5 liter at 1M is 0.5 mol of C6H12O6
so
0.5 * mol mass of glucose
= 0.5 * ( 6*12 + 12*1 + 6*16)
so
0.5 * mol mass of glucose
= 0.5 * ( 6*12 + 12*1 + 6*16)
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