If 5.00g of glucose were to react completely with an excess of oxygen, how many grams of carbon dioxide would be produced?

Answer 1

C6H12O6 + 6O2 => 6CO2 + 6HOH
5g C6H12O6 = (5/180)mole C6H12O6 = 0.028mole C6H12O6

Fm equation ... if ...
1 mole C6H12O6 => 6 moles CO2
then 0.028 mole C6H12O6 => 6(0.028) mole CO2 = 0.468mole CO2 => grams CO2 = (0.468mole CO2)(44g/mol) 20.6g CO2(g)

Answer 2

5/180 = 1/36

1/36 * 6 ( 6 moles of CO2 for everyone one of Glucose) = 1/6

1/6 * 44 = 7.3333333 grams of CO2 produced