A uniform horizontal beam 300N 5m long is suspended vertical from its two end by a rope, if a 600N person stands in 1.5m from its left end find the tension in each end of the rope.

Answer 1

sum of vertical forces: Fl+Fr =300N+600N

sum moments about the left end.
600*1.5- Fr*5=0
Fr=900/ 5 N= 180N

then Fl=900-180=720N