Asked by cath123
                The sum of three consecutive whole numbers is 96.If the lowest number is y then:
a)write down an expression for the other two numbers in terms of y.
b)write down an equation involving y.
c)find y and hence find the other two numbers.
            
        a)write down an expression for the other two numbers in terms of y.
b)write down an equation involving y.
c)find y and hence find the other two numbers.
Answers
                    Answered by
            MsPi_3.14159265
            
    a) y+1 is the next number and the third number is y+2
b) y + (y+1) + (y+2) = 96 , that is the smallest plus the next plus the next :)
c) your turn to solve for y
step1:
y + y + 1 + y + 2 = 96
    
b) y + (y+1) + (y+2) = 96 , that is the smallest plus the next plus the next :)
c) your turn to solve for y
step1:
y + y + 1 + y + 2 = 96
                    Answered by
            peter madison
            
    y + y + 1 + y + 2 = 96
y + y + y = 96-1-2
3y = 93
y= 93,3
y= 31
Is it correct?
    
y + y + y = 96-1-2
3y = 93
y= 93,3
y= 31
Is it correct?
                    Answered by
            Henry
            
    3y = 93,
Y = 31.
    
Y = 31.
                    Answered by
            Henry
            
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