Asked by BBell
A 28 g block sits at the center of a turntable that rotates at 60 rpm. A compressed spring shoots the block radially outward from the center along a frictionless groove in the surface of the turntable. Calculate the turntable's angular speed when the block reaches the outer edge. Treat the turntable as a solid disk with mass with mass 200 g and diameter 44.0 cm. Express your answer in revolutions per minute.
Answers
Answered by
bobpursley
final momentum=initialmomentum
final momentkum= 1/2 (.2*.44)w+.028*w
initial momentum= 1/2 (.2*.44)60
set them equal, solve for w. Notice at the center, r=0, so the block has no angular momentum.
final momentkum= 1/2 (.2*.44)w+.028*w
initial momentum= 1/2 (.2*.44)60
set them equal, solve for w. Notice at the center, r=0, so the block has no angular momentum.
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