Question
A 3.2 kg block sits on a frictionless table that has a hole cut in the middle of it. The 3.2 kg mass is connected to a string that goes through the hole in the table and attaches to a 4.8 kg mass. The 3.2 kg mass moves in a circle of radius 0.2 m
How fast does it have to be moving so thaf the 4.8kg mass does not fall? Also what is the tension in the string?
How fast does it have to be moving so thaf the 4.8kg mass does not fall? Also what is the tension in the string?
Answers
Force up = tension in string = 9.8*4.8 = 47 N
so
47 = m v^2/r
47 = 3.2 * v^2 /.2
v = 1.71
so
47 = m v^2/r
47 = 3.2 * v^2 /.2
v = 1.71
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