Asked by Victoria
How do I prepare 250ml of 0.5M acetic acid by dilution of 3M CH3COOH?
Answers
Answered by
DrBob222
mL1 x M1 = mL2 x M2
250 x 0.5 = mL2 x 3M
Solve for mL2.
250 x 0.5 = mL2 x 3M
Solve for mL2.
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