Asked by Jack
You have a 250ml solution of 0.13M calcium iodate. How many grams of potassium iodate need to be added to the solution to begin to precipitate calcium iodate? The solubility product constant for calcium iodate is6.47 *10^-6. B) you have a 250ml solution of 0.13 M calcium iodate. How many total grams need to be added to the solution until it is saturated in potassium iodate? The ksp for potassium Iodate is 0.183.
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Answered by
DrBob222
I believe this is a screwed up question from the get go.
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